Untuk fixed collector, S = S¬0¬ cos

Untuk fixed collector, S = S¬0¬ cos ɵ, dimana ɵ perubahan pada interval (-ᴨ/2, + ᴨ/2) selama 1 hari. Kecepatan angular dari matahari yang menyebrang dilangit adalah ω = 2ᴨ/T = 7,27 x 10-5 rad/s diferensial dari energi losses adalah dW = IS dt. Jika pengaruh admosfer diabaikan, energi per luasan dapat dihitung dengan persamaan

Results (English) 1:

For fixed collector, S = S¬0¬ cos ɵ, where ɵ changes at the interval (-ᴨ / 2 + ᴨ / 2) for 1 day. The angular velocity of the sun crossing the sky is ω = 2ᴨ / T = 7.27 x 10-5 rad / s is a differential of energy losses dW dt = IS. If admosfer influence negligible, the energy per area can be calculated by the equation

Results (English) 2:

For fixed collector, S = S ¬ cos Ɵ 0, where ɵ changes at intervals (-ᴨ/2, + ᴨ/2) for 1 day. The angular velocity of the sun being crossed over is Ω = 2 ᴨ/T = 7.27 x 10-5 rad/s differential of energy losses is dW = is dt. If the influence of Admosfer is ignored, energy per area can be calculated by the equation